Three Charges inside a Metal Sphere

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SUMMARY

The discussion centers on calculating the charge distribution within a metal sphere and its implications for the electric field. It is established that within a conducting shell, the electric field is zero, allowing for the deduction of net charge on the inner surface. Participants confirm that the charge on a conductor does not need to be uniformly distributed, and they emphasize the straightforward nature of determining the outer surface charge when the shell has zero net charge.

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  • Familiarity with conductors and electric fields
  • Knowledge of charge distribution in conductors
  • Basic mathematical skills for calculations involving charge
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  • Explore charge distribution in non-uniform conductors
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  • Investigate the implications of net charge on electric field behavior
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student49
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Homework Statement
Three fixed point charges of +2 nC, −3 nC and +4 nC are located inside a thin un-
charged metal spherical shell of radius R = 2 cm. Calculate the strength and direction of the electric field at position P, being 10 cm from
the centre of the shell.
Hint
Think Gauss’s Law and carefully consider the conditions within the thickness of the
metal shell and what this tells you about the charge enclosed. Think about concentric
spherical Gaussian surfaces at various radii, and what you can conclude about the net
charge within them. Do NOT simply try and sum up the E~ -fields from the charges,
this does not work here since there is a spherical metal shell in the way.
Relevant Equations
E = Q/(4πE0r^2)

E0 is air permittivity
I know that for a conductor the charge is uniformly distributed and the electric field is zero inside the shell. However, I am not sure how to calculate the charge inside the shell so I can know the electric field.
 
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student49 said:
I know that for a conductor the charge is uniformly distributed
The charge on a conductor does not have to be uniformly distributed.

and the electric field is zero inside the shell.
Yes. E = 0 at each point within the conducting material of the shell. Can you use this fact to deduce the net charge on the inside surface of the shell?
 
TSny said:
Yes. E = 0 at each point within the conducting material of the shell. Can you use this fact to deduce the net charge on the inside surface of the shell?
Did you mean to say "... to deduce the net charge on the outside surface of the shell?"
 
kuruman said:
Did you mean to say "... to deduce the net charge on the outside surface of the shell?"
I was thinking of first deducing the net charge on the inner surface and then using that to deduce the net charge on the outer surface.
 
TSny said:
I was thinking of first deducing the net charge on the inner surface and then using that to deduce the net charge on the outer surface.
Yes, as a first step, that would be the way to proceed. Finding the charge on the outer surface is very easy in this case because the shell carries zero net charge and can be done in one step. Not saying where you were headed with your suggestion made me wonder. All is good. :oldsmile:
 
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