Ti 83 Calculator usage question

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How do you input x=9 on the Ti 83 graph?
 
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Any reason why you want to use it? Are you attempting to vizualize a vertical line test.

Just go to 2nd, draw, vertical... It should show up on the home screen, then just input x=9. Hope that helps.
 
rbzima said:
Any reason why you want to use it? Are you attempting to vizualize a vertical line test.

Just go to 2nd, draw, vertical... It should show up on the home screen, then just input x=9. Hope that helps.
I'm trying to graph functions to find the integral bounds and the area between curves. Now I see how you input it, ok thanks for the help.
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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