Time dependence of kinetic energy in Lagrangian formulation

Click For Summary
SUMMARY

Kinetic energy can explicitly depend on time in the Lagrangian formulation when the inertial Cartesian coordinates are functions of generalized coordinates that also depend on time. This scenario arises in non-inertial reference frames, leading to the expression for kinetic energy as \( T = \frac{m}{2} \left (\dot{q}^k \partial_k \vec{x} + \partial_t \vec{x} \right)^2 \). The discussion confirms that the time derivative of the position vector incorporates both the generalized coordinates and their time dependence, resulting in a time-dependent kinetic energy expression.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with generalized coordinates
  • Knowledge of non-inertial reference frames
  • Proficiency in calculus and vector analysis
NEXT STEPS
  • Study the implications of non-inertial frames on Lagrangian dynamics
  • Explore the derivation of kinetic energy in various coordinate systems
  • Investigate the role of generalized coordinates in classical mechanics
  • Learn about the Einstein summation convention and its applications
USEFUL FOR

This discussion is beneficial for physicists, mechanical engineers, and students studying classical mechanics, particularly those interested in advanced topics related to Lagrangian dynamics and non-inertial reference frames.

Ahmed1029
Messages
109
Reaction score
40
Could kinetic energy possibly depend explicitly on time in the lagrangian for some arbitrary set of generalized coordinates?
 
Physics news on Phys.org
Yes, if the inertial Cartesian coordinates as functions of the generalized coordinates depend explicitly on time (describing the motion in a non-inertial frame of reference) you get from
$$\vec{x}=\vec{x}(q^k,t), \quad k \in \{1,\ldots,f \}$$
the time derivative (Einstein summation convention applies)
$$\dot{\vec{x}}=\dot{q}^k \partial_k \vec{x} + \partial_t \vec{x}$$
and thus
$$T=\frac{m}{2} \dot{\vec{x}}^2 = \frac{m}{2} \left (\dot{q}^k \partial_k \vec{x} + \partial_t \vec{x} \right)^2,$$
which is in general explicitly time dependent.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 43 ·
2
Replies
43
Views
5K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
638
Replies
5
Views
2K