Time period from potential energy expression

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Jahnavi
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Homework Statement


shm.jpg


Homework Equations

The Attempt at a Solution



U = 5x2 - 20x

F = -dU/dx

F = -10x + 20

The expression for force doesn't look like motion is SHM .

How should I deal with this ?
 

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Jahnavi said:

Homework Statement


View attachment 221130

Homework Equations

The Attempt at a Solution



U = 5x2 - 20x

F = -dU/dx

F = -10x + 20

The expression for force doesn't look like motion is SHM .

How should I deal with this ?
What should be the force if a particle performs SHM?
 
ehild said:
What should be the force if a particle performs SHM?

F = -kx

x is the displacement from the mean position .k is constant .
 
Chandra Prayaga said:
What happens if the mean position is not at x = 0?

OK . So the origin is not at the mean position .If it were then F=-kx .

But here mean position is at x= 2 .

Right ?
 
Chandra Prayaga said:
Right. I am sure you can now answer the original question.

Yes :smile:

Thanks !