Deriving an acceleration from Potential Energy

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SUMMARY

The discussion centers on calculating the x-component of acceleration for a 4 kg particle influenced by a conservative force with potential energy defined as U(x) = 6x² + 2. To find the acceleration at x = 1 m, the correct approach involves deriving the force from the potential energy function using the formula Fx = -dU/dx. This leads to the conclusion that the x-component of acceleration can be determined by applying Newton's second law, F = ma, after calculating the force from the potential energy derivative.

PREREQUISITES
  • Understanding of conservative forces and potential energy
  • Knowledge of calculus, specifically differentiation
  • Familiarity with Newton's laws of motion
  • Basic principles of mechanics related to particle motion
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  • Learn how to derive force from potential energy using calculus
  • Study Newton's second law and its applications in particle dynamics
  • Explore examples of conservative forces in physics
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Homework Statement


A 4 kg particle moves along the x-axis under the influence of a conservative force. The potential energy is given by U(x) = ax^2 + b, where a = 6J/m^2 and b = 2J. What is the x-component of the acceleration of the particle when it is
at x = 1 m

Homework Equations



deltaU = -W = -mad ?

The Attempt at a Solution



I'm not quite sure what to do here. I thought I could let U(1) = Ufinal and U(0) = Uinitial so then 6 = -W = -Fd = -mad where d = 1 m

I don't think this works because it's a conservative force along the x-axis so acceleration in mad isn't acceleration due to gravity. I'm pretty lost on this one.
 
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It is not a constant force, so you need to get the derivative of U with respect to x to find the x component of force:

Fx=-dU/dx.

ehild
 

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