Time to React: Calculating the Pilot's Response

  • Thread starter Thread starter Brett
  • Start date Start date
  • Tags Tags
    Response Time
Click For Summary
The discussion revolves around calculating the time a pilot has to raise the nose of a jet flying at 800 mph, 200 feet above ground, before hitting a rising 5-degree slope. The initial calculation provided is (200tan(85))/(800x1.466) seconds, where 1.466 converts speed from mph to feet per second. Participants are encouraged to verify the calculation by using trigonometric principles to ensure the answer is consistent with the triangle formed by the jet's flight path and the slope. The importance of checking calculations through geometric relationships is emphasized. This problem highlights the critical nature of quick decision-making in aviation scenarios.
Brett
Messages
3
Reaction score
0
A jet is flying 200 feet above a level plain at 800 mph. Suddenly, the ground begins to rise at a 5 degree slope. How much time does the pilot have to raise the nose before the aircraft strikes the ground?

I came up with (200tan(85))/(800x1.466) seconds. The 1.466 converts the initial velocity from mph to ft/s, and the 200tan(85) is the distance to the point where the 5 degree slope breaks the level plane.

Can anyone double check this and correct me if I made a mistake?
 
Physics news on Phys.org
looks good to me, remember you can always check your answer in a problem like this by plugging the answer you get back into a triangle and making sure you get the right answer back via trig.

i.e set up a triangle with one side (800 mph *1.466 ft/s/mph *1.95 seconds) and one with side length 200. both of those units are in meters, so you should be able to use inverse tan to find the angle you get back, does it work?

~Lyuokdea
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
4
Views
6K
Replies
13
Views
4K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
3
Views
2K
Replies
7
Views
2K
Replies
2
Views
9K
  • · Replies 1 ·
Replies
1
Views
6K
Replies
2
Views
8K
Replies
11
Views
6K