Solving the Physics Problem: Pilot Flying Over Sloping Ground

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SUMMARY

The physics problem involves a pilot flying horizontally at 1300 km/h, at a height of 35 meters above sloping ground at an angle of 4.3 degrees. To determine the time at which the plane strikes the ground, the relationship between the angle, height, and horizontal distance must be established. The tangent function is utilized, where tan(4.3 degrees) equals the height (35m) divided by the horizontal distance (x). By converting the speed from km/h to m/s, the time can be calculated accurately.

PREREQUISITES
  • Understanding of basic trigonometry, specifically the tangent function.
  • Knowledge of unit conversion from kilometers per hour to meters per second.
  • Familiarity with projectile motion concepts.
  • Ability to solve algebraic equations involving distance, height, and angle.
NEXT STEPS
  • Study the principles of projectile motion in physics.
  • Learn about trigonometric functions and their applications in real-world problems.
  • Practice unit conversion techniques, especially for speed.
  • Explore examples of similar physics problems involving angles and heights.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in applying trigonometry to solve real-world problems involving motion and angles.

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I have this problem to do for homework for my physics class and I don't even know where to start! Could someone try to give me clues?

The problem is:

A pilot flies horizontally at 1300 km/h, at height h= 35 m above initially level ground. However, at time t = 0, the pilot begins to fly over ground sloping upward at angle theta = 4.3 degrees. If the pilot does not change the airplane's heading, at what time t does the plane strike the ground?


thank you so much!
 
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Try to find a way to relate the angle to distance and height.
 
eep said:
Try to find a way to relate the angle to distance and height.

That's what I did for the problem. I used the tan (4.3 degress) = 35m/x. Using that x distance and converting 1300 km/h into m/s, I was able to compute the time.
 

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