Tips for Expressing 8 cos^2 x -6 sin x cos x +2 in rcos(2x+α)+s Form

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AI Thread Summary
The expression 8 cos^2 x - 6 sin x cos x + 2 can be transformed into the form rcos(2x + α) + s by using trigonometric identities. Key identities mentioned include cos 2x = cos^2 x - sin^2 x and sin 2a = 2 sin x cos x. The discussion emphasizes the importance of mastering trigonometric identities for simplification. Participants suggest alternative forms of cos 2x for easier manipulation. Ultimately, the goal is to determine the constants r, s, and α, and to find the maximum and minimum values of the expression as x varies.
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Homework Statement



show that the expression 8 cos^2 x -6 sin x cos x +2 may be expressed in the form rcos (2x+α)+s ,and determine the value of the constants r,s and α.hence ,or otherwise, find the greatest and latest values of the expression as x varies.

Homework Equations



cos 2x=cos^2x-sin^2x ,sin2a=2 sinxcosx ,acos x-bsinx=rcos(x+α)

The Attempt at a Solution


8 cos^2 x -6 sin x cos x +2=8(cos 2x+sin^2x)+3(2 sinxcosx)+2=?
 
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hi kingboy! :smile:

(try using the X2 icon just above the Reply box :wink:)
kingboy said:
cos 2x=cos^2x-sin^2x

learn all your trignonmetric identiies …

in this case, more useful would be cos2x = 2cos2x - 1 :wink:
 
tiny-tim said:
in this case, more useful would be cos2x = 2cos2x - 1 :wink:

agreed :D
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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