Titration: Calculate pH at Equivalence Point (NH3 & HCl)

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SUMMARY

The discussion focuses on calculating the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl, where the Kb of ammonia is 1.8e-5. The correct pH at the equivalence point is established as 5.12, contrasting with the incorrect calculation of 4.98 presented by a participant. Key points include the importance of considering dilution effects and avoiding the use of the Henderson-Hasselbalch equation in this context.

PREREQUISITES
  • Understanding of acid-base titration principles
  • Knowledge of Kb and pH calculations
  • Familiarity with ICE tables for equilibrium calculations
  • Concept of dilution in solution chemistry
NEXT STEPS
  • Study the calculation of pH at equivalence points in titrations
  • Learn about the effects of dilution on pH in titration scenarios
  • Review the use of ICE tables in acid-base equilibrium problems
  • Explore the limitations of the Henderson-Hasselbalch equation in certain titration contexts
USEFUL FOR

Chemistry students, educators, and anyone involved in laboratory titration experiments seeking to enhance their understanding of pH calculations at equivalence points.

woox
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Homework Statement


Calculate the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl? Kb of ammonia is 1.8e-5

This is just a old test I am going over, I managed to get a pH of 4.98. but that is not right the right answer is 5.12 and I can't figure out why. I would assume you could use the henderson equation but I only get 4.98 which is wrong.

Any help?
 
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So show details of your work, hard to say what you did wrong not knowing what you did.
 
Borek said:
So show details of your work, hard to say what you did wrong not knowing what you did.
k... using ICE table below:

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Please reread my very first post in this thread. Every word of it.
 
Borek said:
Please reread my very first post in this thread. Every word of it.

I did and didn not use the HH eq, not do i understand what you mean by dilution.

I also read link, and this is onlything really useful that I understood but still does not explain what I am doing wrong:
In the case of titration of weak base with strong acid, situation is very similar - pH at the equivalence point is determined by the weak base salt hydrolysis. Thus we need pKa of conjugated acid to calculate H+ and pH. Check lecture and cheat sheet mentioned above for details.

It would be great if you told me what I am doing wrong...
 
Try here: dilution effects. Generally speaking, you have mixed two solutions, concentrations have changed as the final volume differs from the initial for each reagent.
 

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