Titration lab with potassium permanganate

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SUMMARY

The discussion focuses on a titration lab involving potassium permanganate and ammonium iron(II) sulphate hexahydrate, specifically addressing the calculation of millimoles in a 1.0000g sample. The balanced chemical equation for the oxidation of iron(II) ions by permanganate is provided: MnO4^- + 8H^+ + 5Fe^2+ ---> Mn^2+ + 4H2O + 5Fe^3+. Participants calculate that 2.5501 millimoles of ammonium iron(II) sulphate hexahydrate are present in the sample and discuss the stoichiometric relationship between permanganate ions and ammonium iron(II) sulphate.

PREREQUISITES
  • Understanding of molar mass calculations
  • Knowledge of stoichiometry and balanced chemical equations
  • Familiarity with titration techniques and procedures
  • Basic chemistry concepts related to oxidation-reduction reactions
NEXT STEPS
  • Study the concept of molar mass and its calculation for various compounds
  • Learn about stoichiometric coefficients in balanced chemical equations
  • Explore titration methods using potassium permanganate as a titrant
  • Investigate the principles of oxidation-reduction reactions in detail
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in analytical chemistry and titration experiments will benefit from this discussion.

cottonz
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Homework Statement


1.The primary standard in thiss experiment is ammonium iron(II) sulphate hexahydrate, (NH4)2Fe(SO4)2*6H2O. Calculate the number of millimoles of ammonium iron(II) sulphate hexahydrate in a 1.0000g sample.

2.Give the balanced equation for oxidation of iron(II) ion by permanganate and find how many millimoles of permanganate ion react with one millimole of ammonium iron(II) sulphate.

3.Calculate the number of millimoles of permanganate ion that titrates 1.0000g of ammonium iron(II) sulphate.

Homework Equations


The balanced equation for 2 is MnO4^- + 8H^+ + 5Fe^2+ ---> Mn^2+ + 4H20 + 5Fe^3+

The Attempt at a Solution


For #1, would I just use 1.0000g x (1mol/molar mass of ammonium iron(II) sulphate hexahydrate) then change the answer into millimoles. I get 2.5501millimoles

For #2, would I use the moles/millimoles I got for #1 and use the ratio from the equation? But where does the ratio come from if ammonium iron(II) sulphate isn't in the balanced equation?
 
Physics news on Phys.org
You know how to calculate number of moles of Fe2+ per mole of Mohr's salt, but you don't know how to calculate number of moles of Mohr's salt that contain a mole of Fe2+? It is the same thing, just the ratio is reversed (which doesn't matter here, as 1/1=1).
 

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