- #1

rnielsen25

- 25

- 1

## Homework Statement

Hi everyone, i have a problem. My brain is short-circuited, and it seems like i can't find out the simplest chemistry in the world :D

We made this experiment where we should determine the sugar content in potato flour. We added amylases to break down the starch to glucose. Then we added fehling's solution and isolated the sediments. Then we added some ammoniumiron(III)sulphate. Last we titrated the solution with potassiumpermanganate.

My problem is that i need to find the molar ratio between the sugar/glucose and the permanganate-ion.

## Homework Equations

The chemical reactions is given by the following reactions.

1. 5OH

^{-}+ RCHO + 2Cu

^{2+}--> RCOO

^{-}+ Cu

_{2}O + 3H

_{2}O

2. 2H

^{+}+ Cu

_{2}O + 2Fe

^{3+}--> 2Cu

^{2+}+ 2Fe

^{2+}+ 2H

_{2}O

3. 8H

^{+}+ 5Fe

^{2+}+ MnO

_{4}

^{-}--> 5Fe

^{3+}+ Mn

^{2+}+ 4H

_{2}O

## The Attempt at a Solution

The molar ratio between RCHO and Cu

_{2}O is 1:1. So is the ratio between Cu

_{2}O in equation 1 and 2.

The molar ration between Cu

_{2}O and Fe

^{2+}is 1:2. So the ratio between RCHO and Fe

^{2+}is also 1:2. But the ratio between Fe

^{2+}in equation 2 and 3 is 2:5. So the ratio between Fe

^{2+}and RCHO is 1:(2*2,5) = 1:5? Because there for every Fe(II) in equation 2 there is 2,5 Fe(II) in equation 3.

But the then the ratio between Fe

^{2+}and MnO

_{4}

^{-}in equation 3 is 5:1.

So the ratio between MnO

_{4}

^{-}and RCHO is what? 5:5? That cannot be true?

My logic says 1:2,5. But i can't explain why. It maked sense to me at first, but when i tried to explain why, i couldn't. Could you help me figure out what the real molar ratio is, and how to explain why it is that? Sorry, that i suddently can't figure out the simplest chemistry and math in the world :D