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b) double the capacitance

WIth the equation U=(1/2)CV^2 doubling the voltage quadruples U and doubling the capacitance doubles U.

However if you double the capacitance in the expression (1/2)Q^2/C you half U instead.

Also, doubling the voltage doubles U in the equation (1/2)QV

So what's the reasoning behind this and where am I confusing myself?