(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A lever is orientated along the y direction in a Cartesian coordinate system. The length of the lever is 0.5m and one end of it is at the origin of the coordinate system. A (3i-5j)N force applied to the other end of the lever. Calculate the Torque produced by the force acting on the lever about the origin. Do calculation twice, firstly using the geometric definition of the cross product and secondly using the algebraic definition of a cross product

L=(0i+0.5j+0k)m

F=(3i-5j+0k)N

2. Relevant equations

T=LFsin(theta)

T=L × F

3. The attempt at a solution

theta= 90+59= -149°

mag F= √(3^2+-5^2)= 5.83N

mag L= .5m

LFsin(theta)= .5*5.83*sin(-149)=T=-1.5Nm

&

(0*-5) - (.5*3) =T=-1.5k Nm

My lecturer has a solution of -2.5Nm! Help appreciated

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Torque- Vector cross product using both geometric and algebraic methods

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