Total gravitational potential energy of four objects

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SUMMARY

The total gravitational potential energy of four masses arranged at the vertices of a tetrahedron with side length "a" is calculated to be -6Gmm/a. This conclusion is derived from the gravitational potential energy formula, which states that the potential energy between two masses is given by -Gmm/r. The error in the initial calculation of -12Gmm/a arises from counting the potential energy contributions of each mass twice. The correct approach involves considering the energy contributions from all unique pairs of masses, resulting in the final answer.

PREREQUISITES
  • Understanding of gravitational potential energy, specifically the formula -Gmm/r.
  • Familiarity with the concept of mass pairs in gravitational interactions.
  • Knowledge of tetrahedral geometry and its properties.
  • Basic principles of work done in bringing masses from infinity.
NEXT STEPS
  • Study the derivation of gravitational potential energy for multiple masses.
  • Learn about the concept of work done in gravitational fields.
  • Explore the properties of tetrahedrons in physics and their applications.
  • Investigate the implications of potential energy in multi-body systems.
USEFUL FOR

Students studying classical mechanics, physicists analyzing gravitational systems, and educators teaching concepts of gravitational potential energy and multi-body interactions.

nhmllr
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Homework Statement


Four masses m are arranged at the vertices of a tetrahedron of side length a. What is the gravitational potential energy of this arrangement?

(answer is -6Gmm/a)

Homework Equations


gravitational potential energy = -Gmm/r


The Attempt at a Solution


One mass is "a" away from another mass. So the gravitational potential energy there is -Gmm/a. But it is attracted to two other masses, so the gravitational potential energy of this one mass is -3Gmm/a. So for all four masses, the total potential energy should be -12Gmm/a, right? So why is this not the answer? Thanks
 
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Imagine removing each object to infinity, one at a time. How much energy is needed for the first, how much for the second...?
 
Potential energy is a function that depends on position (relative to the gravitating masses). The answer does not have any such dependency, which means you are asked about the value of the function at some particular location. Where is it?
 
Assemble the configuration one mass at a time, bringing them in from infinity. To bring in the first mass, no work is done. Bringing in the second mass, the work done is -Gmm/a. Now bringing in the third mass, we must consider the forces from both the masses that have been already been brought in, so the work is the sum -Gmm/a - Gmm/a = -2Gmm/a.

What is the work done in bringing in the third mass?

Once you have them all, add them up.
 
nhmllr said:

Homework Statement


Four masses m are arranged at the vertices of a tetrahedron of side length a. What is the gravitational potential energy of this arrangement?

(answer is -6Gmm/a)

Homework Equations


gravitational potential energy = -Gmm/r


The Attempt at a Solution


One mass is "a" away from another mass. So the gravitational potential energy there is -Gmm/a. But it is attracted to two other masses, so the gravitational potential energy of this one mass is -3Gmm/a. So for all four masses, the total potential energy should be -12Gmm/a, right? So why is this not the answer? Thanks

A point mass alone does not have potential energy. A pair of masses has, and the energy of the pairs add up. You can make 6 pairs from the four masses.

You have counted the potential energy of each mass twice. If mass 1 has potential energy from masses 2, 3, 4, it includes also the potential energy of masses 4,3,2 from mass 1. So you have to divide that -12Gmm/a by two.



ehild
 
Ahhhh I see. Both explanations made a lot of sense. Thanks!
 

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