Total gravitational potential energy of four objects

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Homework Help Overview

The problem involves calculating the total gravitational potential energy of four masses arranged at the vertices of a tetrahedron with a specified side length. The context is rooted in gravitational potential energy concepts and the interactions between multiple masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the gravitational potential energy contributions from individual masses and question the reasoning behind the total energy calculation. There is exploration of the energy required to bring masses from infinity and the implications of counting potential energy for pairs of masses.

Discussion Status

The discussion is active, with participants providing insights into the calculation process and clarifying misconceptions about how potential energy should be summed. Some guidance has been offered regarding the need to consider pairs of masses and the correct way to account for potential energy contributions.

Contextual Notes

Participants are navigating through the complexities of gravitational potential energy, particularly in relation to multiple interacting masses and the assumptions about energy contributions from pairs versus individual masses.

nhmllr
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Homework Statement


Four masses m are arranged at the vertices of a tetrahedron of side length a. What is the gravitational potential energy of this arrangement?

(answer is -6Gmm/a)

Homework Equations


gravitational potential energy = -Gmm/r


The Attempt at a Solution


One mass is "a" away from another mass. So the gravitational potential energy there is -Gmm/a. But it is attracted to two other masses, so the gravitational potential energy of this one mass is -3Gmm/a. So for all four masses, the total potential energy should be -12Gmm/a, right? So why is this not the answer? Thanks
 
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Imagine removing each object to infinity, one at a time. How much energy is needed for the first, how much for the second...?
 
Potential energy is a function that depends on position (relative to the gravitating masses). The answer does not have any such dependency, which means you are asked about the value of the function at some particular location. Where is it?
 
Assemble the configuration one mass at a time, bringing them in from infinity. To bring in the first mass, no work is done. Bringing in the second mass, the work done is -Gmm/a. Now bringing in the third mass, we must consider the forces from both the masses that have been already been brought in, so the work is the sum -Gmm/a - Gmm/a = -2Gmm/a.

What is the work done in bringing in the third mass?

Once you have them all, add them up.
 
nhmllr said:

Homework Statement


Four masses m are arranged at the vertices of a tetrahedron of side length a. What is the gravitational potential energy of this arrangement?

(answer is -6Gmm/a)

Homework Equations


gravitational potential energy = -Gmm/r


The Attempt at a Solution


One mass is "a" away from another mass. So the gravitational potential energy there is -Gmm/a. But it is attracted to two other masses, so the gravitational potential energy of this one mass is -3Gmm/a. So for all four masses, the total potential energy should be -12Gmm/a, right? So why is this not the answer? Thanks

A point mass alone does not have potential energy. A pair of masses has, and the energy of the pairs add up. You can make 6 pairs from the four masses.

You have counted the potential energy of each mass twice. If mass 1 has potential energy from masses 2, 3, 4, it includes also the potential energy of masses 4,3,2 from mass 1. So you have to divide that -12Gmm/a by two.



ehild
 
Ahhhh I see. Both explanations made a lot of sense. Thanks!
 

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