Total momentum operator for free scalar field

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SUMMARY

The discussion centers on the total momentum operator for a free scalar field in quantum field theory. The user expresses confusion regarding the integration over momentum space and the handling of terms involving the annihilation and creation operators, specifically a_{p}a_{-p} and a_{p}^{\dagger}a_{-p}^{\dagger}. The resolution involves recognizing that the commutation of operators allows for cancellation of terms, leading to a simplified final expression. This clarification is crucial for correctly applying the momentum operator in calculations.

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  • Understanding of quantum field theory concepts
  • Familiarity with scalar fields and their operators
  • Knowledge of momentum space integration techniques
  • Proficiency in operator algebra and commutation relations
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This discussion is beneficial for quantum physicists, graduate students in theoretical physics, and researchers focusing on quantum field theory and operator methods.

guillefix
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Sorry for reopening a closed thread. But I have exactly the same doubt as this guy: https://www.physicsforums.com/showthread.php?t=346730
And the answer doesn't actually answer his question. I do get delta(p+p'), but they just help me in getting a_{p}a_{-p} and a_{p}^{\dagger}a_{-p}^{\dagger} Which I don't know how to get rid off, and shouldn't be in the final answer.
 
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You have at last to integrate over d3p. Your unwanted term is p ap a-p, and from the diametrically opposite value of p you'll get -p a-p ap. But the operators commute, so this is equivalently -p ap a-p, which cancels with the first term.
 
Oh true, that's it! Thank you very much!
 

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