Total pressure of water against submarine

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Homework Help Overview

The discussion revolves around calculating the total pressure against a submarine's porthole at a specific depth of 35 meters in seawater with a given density. The context includes understanding the contributions of both the water pressure and atmospheric pressure to the total pressure experienced by the submarine.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relevant equations for pressure in fluids, questioning the appropriate formulas to use for calculating pressure at depth. There are attempts to clarify the distinction between gas and fluid pressure equations.

Discussion Status

The discussion has progressed with participants suggesting potential equations and calculations for total pressure. Some have provided calculations based on the identified formula, while others are still seeking clarity on the concepts involved. There is no explicit consensus, but productive dialogue is ongoing.

Contextual Notes

Participants are working with the assumption that the density of seawater and atmospheric pressure are known, and they are exploring how these factors contribute to the total pressure at depth.

chawki
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Homework Statement


What is the total pressure (absolute pressure) against the porthole of a submarine, when the
submarine is at a 35 m depth, and the density of the seawater is 1020 kg/m3. Air pressure is 1
bar and 1 bar = 1×105 Pa. Give the result using unit bar.

Homework Equations


Total Pressure


The Attempt at a Solution


PV=nRT ?
 
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chawki said:

The Attempt at a Solution


PV=nRT ?

That is for gases.

What is the equation for the pressure given at a certain depth in a fluid? (Hint: The question has most of the relevant quantities that you need in this question)
 


I don't know the equation, and couldn't get anything from the question..except the difference of pressure.
 


ah yesyes...maybe P=density*g*height
 


chawki said:
ah yesyes...maybe P=density*g*height

Right that gives the pressure at the depth 'h'. So at depth 'h', you have that pressure acting in addition to what other pressure?
 


I think the Total pressure would be:
Ptotal=P0+P
Ptotal=105+(1020*9.8*35)
Ptotal=449860 Pa
and that's 4.4986 Bar
 


That should be correct.
 


Thank you :biggrin:
 

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