A 12kg wad of clay is hurled horizontally at a 100g wooden block initially at rest on a horizontal surface. The clay sticks to the block. After impact, the block slides 7.50m before coming to rest. If the coefficient of friction between the bloack and the surface is .650, what is the SPEED of the clay immediately before impact?
This is a perfectly inelastic collision correct?
My book tells me in the answer section to use the following formula, but Im not sure where it came from or why to use this. Am I to use this for equations related to inelastic collisions and friction involved?
1/2(m1+m2)V2^2 = friction(m1+m2)gL
How did it come up with that???? I guess I am just having trouble figuring out how I was suppose to come up with that formula.