Train on 4.4 Incline: Solving for Momentary Rest

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SUMMARY

The discussion focuses on calculating the time it takes for a train car to come to a momentary rest while coasting up a 4.4-degree incline at an initial speed of 3.10 m/s. The user seeks clarification on the interpretation of the incline and the appropriate kinematic equations to apply in this scenario. It is established that the incline rises 4.4 meters for every 100 meters traveled horizontally, corresponding to an angle of 4.4 degrees. The user is advised to decompose the velocity into its x and y components to facilitate the calculations.

PREREQUISITES
  • Understanding of basic kinematics and motion equations
  • Knowledge of vector decomposition in physics
  • Familiarity with trigonometric functions related to angles
  • Ability to apply Newton's laws of motion
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  • Study the kinematic equations for uniformly accelerated motion
  • Learn about vector decomposition techniques in physics
  • Explore the application of trigonometry in resolving forces on inclines
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Manni
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A train is traveling up a 4.4 incline at a speed of 3.10 when the last car breaks free and begins to coast without friction. How long does it take for the last car to come to rest momentarily?

The way I approached it that I reduced the speed to its x and y components. But I don't know what kinematic equations to use that relate the those two dimensions. Help?
 
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By 4.4 incline, does that mean that the incline rises 4.4 meters for every meter that is traveled horizontally? Or vice versa?
 
It means that the train makes an angle of 4.4 degrees relative to a flat surface
 

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