Two Blocks on an Incline: Solving for Acceleration and Tension

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SUMMARY

The discussion focuses on solving a physics problem involving two identical blocks on inclined planes, with angles of 30° and 60°. The solution involves calculating the acceleration of the blocks and the tension in the string under both frictionless and frictional conditions. The equations derived from free-body diagrams are F(box1) = Ftension - mg(sin30) and F(box2) = mg(sin60) - Ftension. The final solution confirms the approach of treating the blocks as a single system to simplify calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of free-body diagrams (FBD)
  • Familiarity with trigonometric functions in physics
  • Basic concepts of friction and its effects on motion
NEXT STEPS
  • Study the derivation of equations of motion in inclined planes
  • Learn about the effects of friction on acceleration in physics problems
  • Explore advanced applications of free-body diagrams in multi-body systems
  • Investigate the role of tension in pulley systems and its calculations
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of problem-solving techniques in dynamics involving inclined planes and tension in strings.

ssgohan434
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SOLVED :)

Homework Statement



https://tycho-s.phys.washington.edu/cgi/courses/shell/common/showme.pl?courses/phys114/winter08/homework/04d/2blocks_incline_NWT/5.gif
The figure shows two identical blocks tied together with a string which passes over a pulley at the crest of the inclined planes, one of which makes an angle q1 = 30° to the horizontal, the other makes the complementary angle q2 = 60°.

a) If there is no friction anywhere, with what acceleration do the blocks move?
b) If each block has a mass m = 1 kg, what is the tension in the string while they are both moving?
c) Now suppose the coefficient of sliding friction between the blocks and planes is µ = 0.02. With what acceleration do the blocks move in this case?

Homework Equations



F = ma
Hint for a): Draw a free-body diagram for each block. Using your free-body diagram and F = ma for each block, find two equations and two unknowns, the unknowns being the acceleration (part (a)) and the tension (part (b)).

The Attempt at a Solution



My freebody diagrams for the box on the left (which I labeled box 1) included a perpendicular normal force, gravity straight down, and tension up the box.
My freebody diagram for the box on the right (box 2) included gravity down, normal force perpendicular to the plane, and tension toward the incline of the plane.

So the equation I came up with:
F=ma --->
F(box1) = Ftension - mg(sin30)
F(box2) = mg(sin60) - Ftension

and that is all I've been able to come up with for the past hour of racking my brain :( . I was hoping someone could point me in the right direction. Much appreciated!
 
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the hint is making it complicated imo, i was taught to do it like this:
a) consider the blocks as one system and ignore tension, draw one FBD for them
b) since you know that the acceleration of both of them will be the same, draw an FBD for one of them and solve for Tension.
c) same as a) except you consider the force of friction
 
Solved :P Thanks afg34 , I ended up basically doing what you said!
 

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