(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A pirate ship is on a waterfall above a fort. The height of the waterfall is 200m above the fort. The pirate captain fires a cannon with an initial velocity 40m/s at angle of 40 degrees. If the cannonball makes a direct hit on the fort, how far away(horizontally) was the pirate ship when it fired.

2. Relevant equations

First find x and y comp.

40cos45=28.28m/s

40sin45=28.28m/s

final velocity^2 = initial velocity^2 +2ad

Final velocity^2= (40^2) + 2(-9.8)(-200)

final velocity= 74.3m/s

final velocity= initial velocity + at

74.3m/s= 40m/s+(-9.8)t

t= 3.5s

Velocity(x-direction) x t= horizontal distance

28.23 x 3.5s = 98.98m

3. The attempt at a solution

98.98m

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# Trajectory Problem: Shooting a cannon

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