Transform y = 5cos3x to y = cos3x + 6

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Homework Help Overview

The discussion revolves around transforming the function y = 5cos(3x) into y = cos(3x + 6). Participants are exploring the implications of changes in coefficients and arguments of the cosine function, particularly focusing on vertical and horizontal transformations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to identify the sequence of transformations needed to transition from one function to the other. Questions are raised about the significance of the coefficient changes and the addition of constants within the function's argument.

Discussion Status

The discussion is active, with participants providing insights into the nature of transformations. Some guidance has been offered regarding the definitions of vertical and horizontal shifts, but there is no explicit consensus on the exact transformations required.

Contextual Notes

Participants are encouraged to recall definitions of translations and expansions/compressions, and there is an emphasis on understanding how changes in the function's parameters affect its graph. The original poster's request for clarity indicates a need for precise definitions in the context of transformations.

Calixto
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Describe a sequence of transformations that would transform the graph of

y = 5cos3x into y = cos(3x + 6)
 
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The 5 in front of the cos(3x) (I assume it's cos(3x), be more clear next time) turned into a 1 in the second function. What does this mean?

The (3x) turned into a (3x + 6). What does this mean?

Recall the definitions of translations and expansions/compressions.
 
Remember that:

Let f(x), ang g(x), be two functions. Then if g(x)=f(x)+k, it means that g(x) is simply the function f(x) shifted up/down wards for k units.
g(x)=f(x+k), it means that g(x) is simply the function f(x) shifted horizontally for k units, either to the right or to the left, depending on the sign of the constant k.
g(x)=kf(x), it means that g is simply the function f, shrinked or extended(or how do you say it) vertically, depending whether |k|>1, or |k|<1.
g(x)=f(kx), is again the function f either extended, or shrinked horizontally, depending on the value of the constant k.

I hope this helps a lill bit.
 
Remember that any change before the given function is applied (in this case 5cos(3x)) is a change in x and any function after the function is a change in y.
changing 5cos(3x) to cos(3x+6) involves 3 changes:
1) Add 6 to 3x. That is, change 3x to 3x+ 6= 3(x+2) or x to (x+ 2). That's the first transformation.
2) change y= cos(3x+6) to y= 5cos(3x+6) or y to 5y. That's the second transformation.
 

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