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Transformation of auxiliary field

  1. Sep 27, 2013 #1

    rbwang1225

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    In West's book "Introduction to Strings and Branes", page 2, I don't understand why the auxiliary field e transformed as e'([itex]\tau'[/itex])d[itex]\tau'[/itex]=e([itex]\tau[/itex])d[itex]\tau[/itex].
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    Last edited: Sep 27, 2013
    rbwang1225, Sep 27, 2013
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  3. Sep 29, 2013 #2

    Korybut

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    By construction :-)

    You impose several conditions on your action and then get how auxilary fields should transform. Just like with YM gauge field, you want gauge invarianceand from this you get transformation law
     
    Korybut, Sep 29, 2013
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