Transition in LS-coupling confusion

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SUMMARY

The discussion centers on the confusion surrounding selection rules in LS-coupling for electric dipole transitions in a two-electron system. Key rules established include Δl = ±1, Δml = 0 or ±1, and Δms = 0. The participants clarify that while ΔL can be 0, it is possible to achieve this by rearranging the vector orientations of l1 and l2, allowing for a change in one of the l values without altering the overall vector sum L. This understanding resolves the apparent contradiction in the selection rules.

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  • Understanding of LS-coupling in quantum mechanics
  • Familiarity with electric dipole transitions
  • Knowledge of angular momentum in quantum systems
  • Basic concepts of vector addition in quantum mechanics
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joris_pixie
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Transition in LS-coupling confusion ! :)

Hello :)
Lets take for example a 2 electron system with l1,s1 and l2,s2. One electron changes energy due to electric dipole.

I understand the rules for electrons in electric dipole transitions:
1) Δl = +/- 1 (parity flips)
2) Δml = 0 or +/- 1
3) Δms = 0

But I don't get a selection rule for the terms !

One of the acceptable transitions is :
ΔL = 0
But if (1) Δl can't be 0 and (2) Δml = 0 or +/- 1 how is this possible ? :)

Because to my understanding L = l1 + l2 in vector form.
 
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joris_pixie said:
One of the acceptable transitions is :
ΔL = 0
But if (1) Δl can't be 0 and (2) Δml = 0 or +/- 1 how is this possible ? :)

Because to my understanding L = l1 + l2 in vector form.
It is possible to rearrange the orientation of the vectors l1 and l2 such that one of the l changes by 1 while the vector sum L doesn't change its magnitude.
 

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