Transition Radiation rates of Hamiltonian

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
6 replies · 2K views
unscientific
Messages
1,728
Reaction score
13

Homework Statement



29p2edt.png


Part (a): Show the Commutation relation [x, [H,x] ]
Part (b): Show the expression by taking expectation value in kth state.
Part (c): Show sum of oscillator strength is 1. What's the significance of radiative transition rates?

Homework Equations


The Attempt at a Solution



Part (a)

Manged to show.

Part (b)

[tex]\langle H \rangle = \langle k|\frac{p^2}{2m} + V|k\rangle[/tex]
[tex]\frac{1}{2m}\langle k|p^2|k\rangle + \langle k|V|k\rangle[/tex]

Not sure what to do at this point - it looks nothing like the answer.
 
Physics news on Phys.org
Instead of taking the expectation value of equation (2.2), take the expectation value of the commutation relation that you showed in part (a).
 
TSny said:
Instead of taking the expectation value of equation (2.2), take the expectation value of the commutation relation that you showed in part (a).

I tried and that leads to nowhere..

[tex]\langle \left[x,[H,x]\right] \rangle[/tex]
[tex]= \langle k|\left[ x, [H,x] \right] |k\rangle[/tex]
[tex]= \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]
 
Last edited:
unscientific said:
I tried and that leads to nowhere..

[tex]= \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]

Keep going. Write out [x,Hx] and [x,xH]. Then judiciously insert the identity operator in the form ##1 = \sum_n |n\rangle \langle n| ##
 
TSny said:
Keep going. Write out [x,Hx] and [x,xH]. Then judiciously insert the identity operator in the form ##1 = \sum_n |n\rangle \langle n| ##

[tex]= \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]
[tex]= \langle k | [x,H]x - x[x,H] |k\rangle[/tex]
[tex]= \langle k | xHx - Hx^2 -x^2H + xHx|k\rangle[/tex]
 
unscientific said:
[tex]= \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]
[tex]= \langle k | [x,H]x - x[x,H] |k\rangle[/tex]
[tex]= \langle k | xHx - Hx^2 -x^2H + xHx|k\rangle[/tex]

Take ##\langle k | xHx |k\rangle## and insert the identity: ##\langle k | x H \hat{1} x |k\rangle##
 
  • Like
Likes   Reactions: 1 person
TSny said:
Take ##\langle k | xHx |k\rangle## and insert the identity: ##\langle k | x H \hat{1} x |k\rangle##
Yeah got it!