Translational Kinetic energy, am i squaring vectors correctly?

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SUMMARY

The discussion centers on calculating the total kinetic energy of a system with three masses: m1 = 5 kg, m2 = 7 kg, and m3 = 5 kg, moving with specified velocities. The user initially attempted to find the kinetic energy using the velocity of the center of mass but encountered inaccuracies in their calculations. The correct approach involves calculating the kinetic energy of each mass separately and then summing these values, rather than relying solely on the center of mass velocity. This conceptual understanding is crucial for accurate kinetic energy computation.

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  • Understanding of translational kinetic energy formulas
  • Knowledge of vector operations, including dot products
  • Familiarity with the concept of center of mass
  • Basic principles of momentum conservation
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  • Calculate kinetic energy for individual masses using the formula K = (1/2)mv²
  • Explore vector dot product calculations in physics
  • Study the concept of center of mass and its implications in multi-body systems
  • Review momentum conservation principles in collision scenarios
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Students studying physics, particularly those focusing on mechanics and kinetic energy calculations, as well as educators seeking to clarify concepts related to momentum and energy in multi-body systems.

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Homework Statement


m1 = 5 kg, v1 = < 11, -4, 12 > m/s
m2 = 7 kg, v2 = < -14, 6, -6 > m/s
m3 = 5 kg, v3 = < -27, 35, 24 > m/s

What is the total kinetic energy of this system?

Homework Equations



Momentum(total) = Mass(total)*Velocty(of Center of Mass)

Ktranslation = (Mass(total)*(Velocity of Ceneter of mass)^2)/2

The Attempt at a Solution



I followed this as close to the textbook as possible and still two ways i did it i got it wrong.

I started off by finding the momentum of the entire system by doing m1v1+m2v2+m3v3. Then i divided that by the total mass (m1+m2+m3). this gave me the velocity of the center of mass.

One i had that i plugged that directly into the equaltion to find the total kinetic energy of the system. v << c, and there is no Kinetic vibrational or rotational energy, so its just translational.

so i plugged that into the K translational formula, but neither solutions i got worked out.

I know my velocity of center of mass is correct at <-10.47, 11.59, 8.118>

So i did the dot product multiplication of that to itsself, and got 309.85. squared that to get 96007.6, then mutiplied by 17/2, to get 816060 Joules, which is not accurate.

(17/2)(<-10.47,11.59,8.118>)^2 = 816060 Joules.

other solution i tried was finding the magnitude of Velocity of center of mass, and squaring that and multiplying it by 17/2. which ends up working out exactly the same.


can someone tell me what I am doing wrong? I've followed every rule and haven't ommitted everything and I've done the problem several times so i know I am not making a small mistake
 
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Think about two masses with equal but opposite momenta. The velocity of the center of mass is zero, but the total kinetic energy of the system is obviously not since the masses are moving. You need to calculate the kinetic energy of the masses separately and then add them up.
 
thanks vela, i should've looked at this more conceptually instead of just jumping in and plugging in numbers
 

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