MHB Triangle $PQR$: Find $\tan P,\,\tan Q,\,\tan R$ Values

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In triangle $PQR$, the values of $\tan P$, $\tan Q$, and $\tan R$ are integers. The discussion revolves around finding these integer values based on the properties of the triangle. Multiple proofs and solutions were proposed, highlighting different approaches to the problem. Participants engaged in sharing their methods and reasoning. The consensus is that the integer values can be determined through geometric relationships inherent in triangle $PQR$.
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In triangle $PQR$, $\tan P,\,\tan Q,\,\tan R$ are integers, find their values.
 
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anemone said:
In triangle $PQR$, $\tan P,\,\tan Q,\,\tan R$ are integers, find their values.

Do not ask me how to derive but the values are

1, 2,3

because i know

$\arctan(1) + \arctan (2) + \arctan (3) = \pi$
 
My solution:

The triple tangent identity says that for angles $x,\,y,\,z$ such that $x+y+z=\pi$, then we must have:

$$\tan(x)+\tan(y)+\tan(z)=\tan(x)\tan(y)\tan(z)$$

And so, as a consequence, we must have:

$$\left(\tan(P),\tan(Q),\tan(R)\right)$$

are one of the six permutations of:

$(1,2,3)$.
 

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Thanks all for participating!:)

Solution proposed by other:

Note that we have $\tan P+\tan Q+\tan R=\tan P \tan Q \tan R$.

Let $\tan P=m$, $\tan Q=n$ and $\tan R=k$, where $m,\,n,\,k$ are integers such that $m+n+k=mnk$.

We can tell $PQR$ cannot be a right triangle.

Now, suppose $\angle P$ is obtuse. Then $m$ is negative while $n$ and $k$ are positive. If $n=k=1$, then $mnk=m<m+2=m+n+k$. Any increase in the values of $n$ or $k$ will increase that of $m+n+k$ while decrease that of $mnk$. It follows that $PQR$ is an acute triangle, so that $m,\,n,\,k$ are all positive.

We may assume that $k \ge n \ge m$. Then $mnk=m+n+k \le 3k$, so that $mn \le 3$. We cannot have $m=n=1$, hence $m=1$, $n=2$, $k=3$.
 
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