Trigonometry Problem: Finding Distances in Sodium Chloride Crystal Structure

  • Thread starter Thread starter 1irishman
  • Start date Start date
  • Tags Tags
    Trigonometry
Click For Summary

Homework Help Overview

The problem involves finding the distance between sodium and chloride ions in a sodium chloride crystal structure, represented as a cube with a specified edge length. The original poster is attempting to calculate the distance between two ions located at opposite corners of the cube.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the Pythagorean theorem and the distance formula in three-dimensional space to approach the problem. There are questions about visualizing the problem and how to represent it geometrically.

Discussion Status

The discussion is ongoing, with some participants providing detailed explanations of the distance formula and its geometric implications. The original poster expresses appreciation for the guidance received, indicating that they are beginning to understand the concepts involved.

Contextual Notes

There is a mention of the difficulty in conceptualizing the problem and the need for visual representation, which may affect the understanding of the solution approach.

1irishman
Messages
243
Reaction score
0
1. Homework Statement
A drawing shows sodium and chloride ions positioned at the corners of a cube that is part of the crystal structure of sodium chloride. The edge of the cube is 0.281nm in length. Find the distance between the sodium ion located at one corner of the cube and the chloride ion located on the diagonal at the opposite corner.


2. Homework Equations
I'm thinking pythagorean theorem and one or more of the trig functions perhaps?


3. The Attempt at a Solution
Well...I figured the diameter if the cube is drawn inside a circle is 2(0.281)=0.562nm.
Not sure what to do this...it's difficult for me to conceptualize.

(The answer in the book is 0.487nm)
 
Physics news on Phys.org
One way to approach this is as a distance problem in 3-D space. Put on corner of the cube at the origin - (0, 0, 0) - and the opposite corner at (.281, .281, .281).

The distance d from a point (x1, y1, z1) to another point (x2, y2, z2) is
d~=~\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}

BTW, I get a distance of 0.48670627692685451948121242196315 nm.
 
I kind of understand, but what would this look like as a picture on paper? Imagine no numbers...
 
Unfortunately, I am unable to draw you a picture. The distance formula in my previous post is the 3-D counterpart to the length of the hypotenuse in the Theorem of Pythagoras.

I'll try to describe what this formula does in words, and leave the drawing to you. In your NaCl cube, let's say that you want to find the distance from the lower left corner (O) of the front face, to the upper right corner (P) of the rear face. To find this distance, consider the triangle whose vertices are O, P, and the point at the lower right corner of the front face (call this point Q). Triangle OPQ is a right triangle, with the right angle formed by sides OQ and OP. By the theorem of Pythagoras, |OP| = sqrt(|OQ|2 + |QP|2). |OQ| is given in your problem, and |OQ| is the length of the diagonal across one of the square faces.

Hopefully I have described this well enough so that you can draw the picture.
 
Thank you for this very detailed help. I appreciate the effort you put into helping me construct a picture if you will. It does make sense to me after I drew it based on your instructions. Thanks again.
 

Similar threads

Replies
3
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
1
Views
3K
Replies
4
Views
14K
Replies
6
Views
1K
Replies
11
Views
17K
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 7 ·
Replies
7
Views
4K