Ive been working this problem for the past hours, and i keep getting the wrong answer... can someone check to see what I am doing wrong, and please correct me.. Question: An 18g object moving to the right at 26cm/s overtakes and collides elastically with a 33g object moving in the same direction at 16cm/s. I need to find the velocity of the slower object and then the faster object. My attempt at this question: m1v1 + m2v2 = m1v1f + m2v2f (.018)(26) + (.033)(16) = (.018)v1f + (.033)v2f (.468) + (.528) = (.018)v1f + (.033)v2f (.996)= (.018)v1f + (.033)v2f then KE cons. 26-16 = -(v1f-v2f) 10=v1f + v2f v1f = -10 + v2f and subsituted (v1f = -10 + v2f) in v1f in the first eq. (.996)= (.018)(-10 + v2f) + (.033)v2f (.996)= (-.180) + (.018)v2f + (.033)v2f (.996)= (-.180) + (.051)v2f (1.176)= (.051)v2f (1.176/.051) = v2f v2f= 23.05882 (((<<< this is for the slower object))) For the faster object I work the problem the same way, only using the substitution for v2f this time. And Its incorrect. please help!