Trouble with mirror equations, .

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Homework Help Overview

The discussion revolves around mirror equations in optics, specifically focusing on the characteristics of concave and convex mirrors and their respective calculations for image distance and radius of curvature.

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  • Mixed

Approaches and Questions Raised

  • Participants explore the calculations related to image distance and focal length using mirror equations. There is a focus on the signs of object and image distances, as well as the implications of magnification values. Questions arise regarding the interpretation of negative values in the context of convex mirrors and the nature of the images produced.

Discussion Status

Some participants provide clarifications on the correct usage of signs in the equations, while others express confusion about the implications of negative values for image distance and magnification. The conversation indicates a productive exploration of concepts without reaching a definitive conclusion.

Contextual Notes

Participants are navigating the rules of sign conventions in optics, particularly in relation to concave and convex mirrors, and how these affect calculations and interpretations of image characteristics.

x64bob
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heres the problem:
a dentist wants a small mirror that, when 2.20cm from a tooth, will produce a 4.5x upright image. what kind of mirror must be used and what must its radius of curvature be?

so i did the following calculations with the mirror equations i learned:

m=4.5

equation to get the di https://www.physicsforums.com/attachment.php?attachmentid=7885&stc=1&d=1159712057

4.5*(-2.20) = di di=-9.9

1/do+1/di=1/f

1/(-2.2) + 1/(-9.9) = 1/f

1/(-2.2)=(-0.454545455)
1/(-9.9)=(-0.101010101)

(-0.454545455)+(-0.101010101)=(-0.555555556)

1/(-0.555555556)=f

1/(-0.555555556)=(-1.8)

f=(-1.8)

f2 = r

-1.8 * 2 = -3.6

so the radius is -3.6 and i guess it is concave as only concave mirrors 1.0+ magnify? that's wrong as my book says the correct answer is 5.66cm, concave. what am i doing wrong:confused:
 

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x64bob said:
1/do+1/di=1/f

1/(-2.2) + 1/(-9.9) = 1/f
The object distance should be +2.2, not -2.2.
 
ok, thanks a lot. so doesn't "- di/2.2" mean that both di and 2.2 are negative values?
 
x64bob said:
so doesn't "- di/2.2" mean that both di and 2.2 are negative values?
Not sure what you mean. Think of it this way. You know that do is positive: do = +2.2 cm. The magnification is positive, since the image is upright: m = +4.5. Since m = -di/do, that tells you that di is negative: di = -m*do = -9.9 cm.
 
what about convex mirrors? can i use exactly the same equations for them? on my next task (m=0.33 do=20) i had to calculate the radius for this convex mirror and i got -19.7, so if - means that the image is inverted, and as far as i know convex ones don't generate inverted images, should i remove the - or something?

and does a magnification of 2.0 mean that the di is just twice as short as do while m0.5 means that di is twice as long as do?
 
x64bob said:
what about convex mirrors? can i use exactly the same equations for them?
The basic equations are the same.
on my next task (m=0.33 do=20) i had to calculate the radius for this convex mirror and i got -19.7, so if - means that the image is inverted, and as far as i know convex ones don't generate inverted images, should i remove the - or something?
A negative magnification means that the image is inverted, but a negative radius just means that the mirror is convex.

and does a magnification of 2.0 mean that the di is just twice as short as do while m0.5 means that di is twice as long as do?
No, just the opposite. Review the definition of magnification, given by the equation: m = -di/do

So a magnification of 2.0 means that di is twice as long as do.
 

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