True or False Integral Calculus Question #3

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SUMMARY

The discussion centers on the evaluation of a statement regarding Riemann sums and integral calculus. It concludes that if \( f(x) \) is a negative function with \( f'(x) > 0 \) for \( 0 \leq x \leq 1 \), the right-hand Riemann sums yield an overestimate of the integral \( \int_{0}^{1} (f(x))^2\,dx \). This is because squaring the negative function transforms it into a positive, increasing function, leading to an overestimate when applying right-hand Riemann sums.

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  • Familiarity with the behavior of functions and their derivatives
  • Concept of squaring functions and its impact on their properties
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True or False: If $f(x)$ is a negative function that satisfies $f'(x) > 0$ for $0 \le x \le 1$, then the right hand sums always yield an underestimate of $\int_{0}^{1} (f(x))^2\,dx$.

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Would it be true since right hand Riemann sums for a negative, increasing function will always produce an underestimate for the integral, so it doesn't really matter if the entire "function" we're dealing with is squared?
 
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$(f(x))^2\ge0$
 
Or... would it be that squaring $f(x)$ will turn $f(x)$ into a positive function from a negative function, so the statement is going to be false because taking the right Riemann sum will still give you an overestimate for positive, increasing functions?
 
Yeah, OK. So, in that case, it becomes a positive, increasing function, so it's an overestimate, right?
 
That's right.
 

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