Trying to find displacement using velocity and acceleration

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A train traveling at 60.0 m/s decelerates at a rate of 1.25 m/s², and the goal is to find the distance it travels before reaching half its original speed. The relevant equation used is v² = vo² + 2ad, but the user struggles with isolating the displacement variable 'd' correctly. After attempting to manipulate the equation, they arrive at a negative distance, which is nonsensical, indicating a misunderstanding of the formula. The discussion emphasizes the need for correct algebraic manipulation and encourages sharing detailed calculations for further assistance. Clarity in the application of physics equations is crucial for solving displacement problems.
mrsconfused
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Homework Statement


A train traveling at a velocity of 60.0 m/s is slowed down at a uniform rate of 1.25 m/s2. How far will it travel before its velocity is 1/2 its original value?


Homework Equations


v2 = vo2 + 2ad


The Attempt at a Solution


I first need to isolate my variable, so 'd'. In which case, I believe the equation would then look like 'd=vo2 \div v2+2a. Filling in this equation with the numbers then looks like: d=60m/s2\div30m/s2+2(-1.25m/s2). But when I calculate it all out I'm left with d=-0.5m/s2. This does not make any sense though; it's not possible for the train to travel a negative amount of distance. And also, isn't displacement measured in units of length and not time? I can't figure out how to get rid of the seconds. Needless to say, I am very confused. Thanks in advance.
 
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mrsconfused said:
I believe the equation would then look like 'd=vo2 \div v2+2a.
I don't. Try that manipulation again. If you're still stuck, post your detailed working.
 
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