Kinematic Equations Homework Solutions

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Homework Help Overview

The discussion revolves around kinematic equations, specifically addressing problems related to displacement, velocity, and acceleration in various scenarios. Participants are analyzing the correctness of their calculations and the application of relevant equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss their attempts to solve problems involving kinematic equations, questioning the accuracy of their results and the methods used. Some inquire about the SUVAT equations and their application in the context of the problems presented.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the accuracy of their answers and the methods employed. Some guidance has been offered regarding the use of SUVAT equations, and there is an exploration of potential inaccuracies in the calculations presented.

Contextual Notes

Participants express concerns about the precision of their answers and the implications of using intermediate results in calculations. There is a focus on ensuring that the equations used are appropriate for the scenarios described.

alexandria
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Homework Statement


upload_2016-3-21_23-25-15.png


Homework Equations


relevant equations are listed with each question

The Attempt at a Solution



25. **

Displacement = 131 km (South)

Average velocity = total displacement / total time

Average velocity = 131 km (S) / 2.0 h

Average velocity = 65.5 km /h (south)


26. **

Given information:

v1 = 75 km/h

Convert to m/s:

(75 km/h) x (1000 m/1 km) x (1 h/3600 s) = 20.8 m/s

d = 42 m

total time = 3.4 s

a)

Calculate acceleration:

a = v2 – v1 / total time

a = 0 – 20.8 m/s / 3.4 s

a = -6.12 m/s2

Calculate distance:

total distance= v1(total time) + ½ a (total time)^2

= (20.8 m/s) x (3.4 s) – ½ (6.12 m/s2) x (3.4 s)2

= 35.35 m

Andrew traveled 35.35 m before stopping.b) ***

Andrew did not hit the fox.

42 m – 35.35 m = 6.65 m
c) ***

35.35 m / 4.2 m = 8.4 m

It took approx. 8 van lengths for Andrew to stop.


27. **

Given information:

v1 = 2.1 m/s (up)

total time = 3.0 s

acceleration = -9.81 m/s2 (down)

a)

Equation:

total displacement = v1(total time) + ½ a (total time)^2

Substitute and solve:

d = (2.1 m/s) x (3.0 s) – ½ (9.8 m/s2) x (3.0 s)^2

d = -37.8 = 37.8 m

Marian’s Balcony is 37.8 m high.

b)

v2^2 = v1^2 + 2a(total displacement)

= (2.1 m/s)2 + 2(-9.8 m/s2) x (-37.8 m)

= √746

= 27.3 m/s (down)

 

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That's all about right, but you could have used a shorter and more accurate path in 27 a) and b).
In a) do you know a SUVAT equation relating acceleration, time, initial speed and distance?
In b) do you know a SUVAT equatiom relating initial speed, final speed, time and acceleration?
(Using an intermediate result, as from 27a), as input to a further result often leads to loss of precision. E.g. while it might be appropriate to quote an intemediate result to 3 digits, you should use at least four as input to the next step.)
 
can you explain what SUVAT equations are?
 
so for questions 25, and 26 are they completely correct?
and when you say 'shorter and more accurate path to solve 27 a) and b)' do u mean that the answers are not as accurate as they should be? did i do it right or wrong?
 
alexandria said:
so for questions 25, and 26 are they completely correct?
and when you say 'shorter and more accurate path to solve 27 a) and b)' do u mean that the answers are not as accurate as they should be? did i do it right or wrong?
They could be a bit more accurate. 27b is out by about 1 percent, whereas quoting three significant figures here implies about 0.3% or better.
It's not a question of right or wrong. Using the best choice of equations from the SUVAT collection would have involved less working and produced more accurate answers.
 
i see,
what about 25 and 26, i feel like I am missing something
 
alexandria said:
i see,
what about 25 and 26, i feel like I am missing something
Why? They look fine to me.
 
ok thanks just clarifying :smile:
 

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