Trying to find mass given force, distance, and time.

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SUMMARY

The discussion focuses on calculating the mass of a block of ice subjected to a constant horizontal force of 70.0 N over a distance of 11.0 m in 4.80 seconds. The correct approach involves using the equation F = m*a, where acceleration (a) must be determined using the formula d = vi*t + (1/2)*a*t^2. The initial attempt incorrectly applied average speed instead of deriving acceleration from the distance and time. Additionally, the second part of the problem requires calculating the distance the block moves after the force is removed, which necessitates understanding of kinematic equations.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m*a)
  • Knowledge of kinematic equations for constant acceleration
  • Ability to manipulate algebraic equations
  • Familiarity with basic physics concepts such as force, mass, and acceleration
NEXT STEPS
  • Study kinematic equations, specifically d = vi*t + (1/2)*a*t^2
  • Learn how to derive acceleration from force and mass using F = m*a
  • Explore the concept of motion after force application ceases
  • Practice problems involving constant acceleration and frictionless surfaces
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Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for problem-solving strategies in force and motion scenarios.

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Homework Statement



A dockworker applies a constant horizontal force of 70.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 11.0 m in a time 4.80 s

Homework Equations


A)What is the mass of the block of ice?
B)If the worker stops pushing at the end of 4.80 s, how far does the block move in the next 4.20 s?


The Attempt at a Solution


A)F=m*a, 70.0=x*11.0/4.80
70.0/(11.0/4.80)=x, x=30.5 which was wrong.
B)I have absolutely no idea where to start or what to do on this part.
 
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welcome to pf!

hi jad6016! welcome to pf! :wink:
jad6016 said:
A)F=m*a, 70.0=x*11.0/4.80

no, you've used a = distance/time, which is wrong …

use one of the standard constant acceleration equations to find a :smile:
 
find first the acceleration
derive the d=vit+1^2at^2
that's what i think
 

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