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Help with Newton's Law Acceleration Problem

  1. Feb 23, 2013 #1
    1. The problem statement, all variables and given/known data

    A dockworker applies a constant horizontal force of 83.0 to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 10.0 in a time 5.30 .

    If the worker stops pushing at the end of 5.30 , how far does the block move in the next 4.20?

    2. Relevant equations

    d=v(i)t+.5at^2
    a=(vf-vi)/t

    3. The attempt at a solution

    I solved Vi by dividing distance/time, and then solved for acceleration (-.449235) by dividing (Vf-Vo)/t with Vf=0 and Vi=1.88. I used 4.20 as "t". I plugged the results into d=v(i)t+.5at^2 and got 3.96 as an answer, however masteringphysics said I was wrong. What am I doing wrong??
     
  2. jcsd
  3. Feb 23, 2013 #2

    jedishrfu

    Staff: Mentor

    vi stands for vinitial which is ZERO in this case as the block starts from rest. Given that you can solve for a and then the velocity at 5.30 secs
     
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