Trying to show that rationals exist on the + real number line field K

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SUMMARY

The discussion focuses on demonstrating the existence of rational numbers within the positive real number line field, denoted as K. The user presents a mathematical framework using the notation of sets, specifically stating that both the positive reals (ℝ+) and rationals (ℚ) are subsets of K. The conclusion drawn is that for every element ε in ℝ+ and c in ℚ, there exists an intersection of these sets within K, affirming the relationship between these number sets.

PREREQUISITES
  • Understanding of set theory and notation in mathematics
  • Familiarity with fields in linear algebra
  • Knowledge of rational and real number properties
  • Basic skills in mathematical proofs and logical reasoning
NEXT STEPS
  • Study the properties of fields in linear algebra, focusing on ℝ and ℚ
  • Explore set theory concepts, particularly intersections and subsets
  • Learn about mathematical notation and its proper usage in proofs
  • Investigate the implications of closure properties in fields
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Students of linear algebra, mathematicians interested in number theory, and educators looking to enhance their understanding of the relationships between different number sets.

CubicFlunky77
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This is the first 'problem' in my Linear Algebra/Geometry textbook. I just need to know if I am doing it correctly. Any hints? I also need to know if I am using correct notation/presentation.

Question: [itex]\mathbb R^+ \leftrightarrow \mathbb Q[/itex]?

What I've done:

Suppose: [itex](ε_1,...,ε_n) \in \mathbb R^+ \rightarrow \mathbb K[/itex] and
[itex](c_1,...,c_n) \in \mathbb Q \rightarrow \mathbb K[/itex]


Assuming: [itex]\mathbb R^+ ⊂ \mathbb K[/itex] and [itex]\mathbb Q ⊂ \mathbb K[/itex] where [itex]\mathbb K[/itex] is a numerical/object field; we can say that


[itex]\forall (ε \in \mathbb R^+, c \in \mathbb Q) \in \mathbb K \exists (ε \cap c) \in (\mathbb R^+ \bigcap \mathbb Q)[/itex] |[itex]\mathbb R^+ \leftrightarrow \mathbb Q[/itex]
 
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I'm not sure I understood what you meant, but you can do this:

i)1 is in ℝ , 1 as the identity, since ℝ is a field.ii) 1+1=2 is in ℝ , by closure of operations

iii) (1+1)(-1)=1/2 is in ℝ , since every element in a field is invertible

iv)... Can you take it from here ( if this is what you meant)
 
I get it, thanks!
 

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