Trying to solve the Poschl-Teller potential

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SUMMARY

The discussion focuses on solving the Poschl-Teller potential in quantum mechanics using a superpotential defined as W(x) = -b * cot(x). The two Poschl-Teller potentials derived are J(x,b) = b(b-1)/(sin(x))^2 - b^2 and K(x,b) = b(b+1)/(sin(x))^2 - b^2. The user attempts to apply the Schrödinger equation, resulting in two differential equations, but seeks guidance on transforming these into a form involving Legendre polynomials by substituting u = cos(x).

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  • Understanding of quantum mechanics principles, specifically the Schrödinger equation.
  • Familiarity with the Poschl-Teller potential and its applications.
  • Knowledge of differential equations and their solutions.
  • Experience with Legendre polynomials and their properties.
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  • Study the transformation of differential equations using variable substitutions, particularly u = cos(x).
  • Learn about the properties and applications of Legendre polynomials in quantum mechanics.
  • Explore advanced techniques for solving the Schrödinger equation with non-constant potentials.
  • Investigate the implications of the Poschl-Teller potential in quantum mechanics and its relevance to bound states.
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Students and researchers in quantum mechanics, particularly those studying potential wells and differential equations related to the Schrödinger equation.

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Trying to solve the Poschl-Teller potential (quantum mechanics)

Homework Statement


I have a superpotential that give me 2 of the Poschl-Teller potentials.
The superpotential is:
W(x)=-b*cot(x)
The Poschl-Teller potentials are:
J(x,b)=b(b-1)/(sin(x))^2-b^2
K(x,b)=b(b+1)/(sin(x))^2-b^2

Homework Equations


Schrödinger equation: Hψ=Eψ

The Attempt at a Solution


I placed the potential in Schrödinger equation (neglecting the existence of constants) and received the following equations:
ψ''(x)+(2E-J)ψ(x)=0
ψ''(x)+(2E-K)ψ(x)=0
I do not know what the next step I should do
I know I need to get to Legendre polynomial but I don't know how...
Can anyone show me how to do it?
 
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Put [itex]u=\cos x[/itex]. Rewrite the DE in the u variable...
 

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