Two quotient groups implying Cartesian product?

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SUMMARY

The discussion centers on the structure of a group G with two normal subgroups H_1 and H_2, where H_1 ∩ H_2 = {0}, H_1 = G/H_2, and H_2 = G/H_1. It concludes that G can be expressed as a direct product G = H_1 × H_2 under the condition that the representation is unique and the group is finite (|G| < ∞). The author suggests that if this uniqueness holds, G can also be represented as a semidirect product. The case for infinite groups remains unresolved.

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  • Understanding of group theory concepts, specifically normal subgroups.
  • Familiarity with direct products and semidirect products in group theory.
  • Knowledge of finite and infinite group properties.
  • Proficiency in additive group notation and projections in group theory.
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  • Study the properties of normal subgroups in group theory.
  • Learn about the conditions for direct and semidirect products of groups.
  • Research the implications of group finiteness on structure and representation.
  • Explore examples of groups that illustrate the concepts discussed, particularly infinite groups.
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Mathematicians, particularly those specializing in abstract algebra, group theorists, and students seeking to deepen their understanding of group structures and their implications.

jostpuur
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Assume that G is some group with two normal subgroups H_1 and H_2. Assuming that the group is additive, we also assume that H_1\cap H_2=\{0\}, H_1=G/H_2 and H_2=G/H_1 hold. The question is that is G=H_1\times H_2 the only possibility (up to an isomorphism) now?
 
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I think if the representation G= H_1 \times H_2 [/ itex] is unique, then G can be expressed as a semidirect product.
 
I think I managed to prove the claim by using the projections G\to H_1 and G\to H_2 given by the assumptions, under the assumption \#G&lt;\infty, which I did not mention above. Since I was the one asking this, there is probably no need for me to post the full proof, and this will remain as a challenge to the rest. The case \#G=\infty remains open.
 
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