Two-tailed Test: Rejecting the Null at 0.05 Level of Significance

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SUMMARY

In a two-tailed test with a test statistic value of 2, the associated P-value is P(T>2) = 0.03. This indicates that there is insufficient evidence to reject the null hypothesis at the 0.05 level of significance, as the critical P-value for each tail is 0.025. Therefore, the conclusion is that the null hypothesis cannot be rejected based on the provided data.

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In a two-tailed test, the value of the test statistic is 2. If we know the test statistic follows a Student’s t- distribution with P
(T>2) = 0.03, then we have sufficient evidence to reject the null hypothesis at 0.05 level of significance.

I want to say True but I think I'm overthinking the problem. Can anyone help me out?
 
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The problem is, it's a two-tailed test. If you take $0.05$ as your significance level, then you'd need $0.025$ probability in each tail. But your $P$ value is $0.03>0.025$. Therefore, you do not have sufficient statistical evidence to reject the null hypothesis.
 
Yes! I get tripped up working backwards on problems. two-tailed - 0.05/2 = 0.025. I understand - thank you! I feel silly now on such a simple problem.
 

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