Ultrasonic Standing Wave Suspension could the transducer support itself?

Click For Summary
SUMMARY

The discussion centers on the feasibility of using ultrasonic standing wave suspension to support a transducer itself, referencing Hemsel (2013). It highlights that a surface area of 1m² can support 11.5 kN at 16 Watts, raising the question of whether the transducer can suspend itself from the reflector. The calculations suggest that to lift 1.15 metric tons, approximately 5 kW of power would be necessary, taking into account peripheral losses and scaling effects.

PREREQUISITES
  • Understanding of ultrasonic standing wave suspension principles
  • Familiarity with power calculations in mechanical systems
  • Knowledge of transducer technology and its applications
  • Basic grasp of wave mechanics and surface area effects
NEXT STEPS
  • Research the principles of ultrasonic standing wave suspension in detail
  • Explore power requirements for lifting mechanisms using transducers
  • Investigate the impact of surface area on lift capacity in ultrasonic systems
  • Study the efficiency and losses in ultrasonic transducer systems
USEFUL FOR

Engineers, researchers, and students in the fields of mechanical engineering, acoustics, and materials science who are interested in advanced suspension technologies and their practical applications.

tony two takes
Messages
7
Reaction score
0
Ultrasonic Standing Wave Suspension could the transducer support itself?

Essentially looking at items that state a surface area of 1m2 could support 11.5kn at 16 Watts (Hemsel, 2013) could the transducer suspend itself from the reflector using the same theory even though the suspension point is at the second wave from the transducer if it were within the parameters of weight to surface area?

References.

Hemsel (2013) http://mb.uni-paderborn.de/en/mud/research/piezoelectric-and-ultrasonic-systems/atomization-and-suspension-using-ultrasonic-standing-wave-patterns/
 
Last edited by a moderator:
Engineering news on Phys.org
I fear you overlooked something.
They state clearly : "The first system was able to lift a weight of 3 kg using an electrical input power of only 16 W. Based on the surface area, a lift capacity of 11.5 kN/m2 was reached."
11500/30 ~ 380; 16W* 380 ~ 6000W, so even assuming peripheral losses will diminish when you scale up, 5kW seems to be a more reasonable estimate of the power required to lift 1.15 (metric) tons, given the technology used.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K