Ultraviolet Catastrophe & the Photoelectric Effect

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SUMMARY

The discussion centers on the Ultraviolet Catastrophe and the Photoelectric Effect, highlighting the limitations of classical physics in predicting electromagnetic radiation emission. Classical physics, represented by the Rayleigh-Jeans law, inaccurately suggests that objects like pens emit equal amounts of UV and infrared light, failing to account for quantization. Additionally, the necessity of charging a gold leaf electroscope before demonstrating the photoelectric effect is clarified, as uncharged electroscopes exhibit a significantly weaker response to photoelectron emission, making the experiment challenging.

PREREQUISITES
  • Understanding of Rayleigh-Jeans law
  • Familiarity with the concept of quantization in physics
  • Knowledge of the photoelectric effect and its implications
  • Basic principles of electromagnetic radiation
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  • Research the implications of the Rayleigh-Jeans law on blackbody radiation
  • Study the principles of quantum mechanics related to photon emission
  • Explore practical demonstrations of the photoelectric effect using charged and uncharged electroscopes
  • Investigate the historical context and significance of the Ultraviolet Catastrophe in physics
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Students of physics, educators explaining quantum mechanics, and researchers interested in the historical development of electromagnetic theory.

Jimmy87
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Hi,

Please could somebody verify if what I have understood about the UV catastrophe is along the correct lines. I used this hyperphysics link:

(http://hyperphysics.phy-astr.gsu.edu/hbase/mod6.html)

Is it saying that using classical physics an object like a pen should be emitting just as much UV light as infrared? The way I understand it is that an object like a pen is absorbing energy all day but also emitting the energy back and this energy being emitted back should have equal probability of being infrared, visible, UV (as per the table in the above link)? So as an example, let's say after 5s a pen absorbs 100eV of energy from the room. Since UV photons have an energy of around 10eV then this energy could hypothetically (at least classically) be emitted back as 10 UV photons rather than what actually happens which is that 100 infrared photons (1eV each) are emitted back. Is this basically what classical physics had to say about what EM radiation objects should emit?

Could someone also explain why a gold leaf electroscope has to be charged before it demonstrates the photoelectric effect. In all online demos I have seen a charged rod is brought close and the person touches the top to allow electrons to flow onto the electroscope causing the leaf to stay deflected after the rod is removed. Why can't a neutral electroscope be used? If it is not charged initially then the leaf would be down but if you shine UV light on the top then surely electrons would still come off leaving the electroscope positively charged and therefore the leaf would start to rise?
 
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Jimmy87 said:
Hi,Is it saying that using classical physics an object like a pen should be emitting just as much UV light as infrared?

Not exactly. classical physics do not operate with "photons" at all, it just produce Raileigh-Jeans law which is grossly inaccurate at ultraviolet wavelengths exactly because it does not take quantization into account.
https://en.wikipedia.org/wiki/Rayleigh–Jeans_lawRelating electroscope effect charging by photoelectron emission instead of discharging, the effect do definitely exist but simply much weaker (by factor of ~100) so experiment is difficult to perform.
 
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