Uncover the Mystery of Numbers: Always Ending up with 9

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SUMMARY

The discussion centers on the mathematical phenomenon where subtracting the sum of a number's digits from the original number results in a value that, when reduced to a single digit, is always 9. This occurs because a number and the sum of its decimal digits are congruent modulo 9, making their difference divisible by 9. This principle is illustrated through examples such as 22 and 14567, and is related to the traditional arithmetic technique known as "casting out nines."

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  • Familiarity with digit summation techniques
  • Basic knowledge of number theory concepts
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Dave9600
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Take any whole number and add the digits down to a single number. Now, subtract this number from the original number. With this answer add the digits down to a single number and it will always end up being 9.

Example: 22 (2+2=4) 22-4=18 (1+8=9)

or
14567 (1+4+5+6+7=23 and 2+3=5) 14567-5=14562 (1+4+5+6+2=18 and 1+8=9)

Why does you always end up with 9 and is there a name for this?
 
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A number and its sum of its decimal digits are equivalent to each other mod 9, so their difference is divisible by 9.
 
Hi Dave9600! :smile:

Because when you replace eg 50000 by 5, you reduce the number by 5 times 9999, which is obviously divisible by 9.

Add all the 50000s etc, and add all the 5s etc, and then subtract, and the result is divisible by 9.

In numbers: ∑ an10n - ∑ an

= 9(∑ ani<n10i) :wink:
 
And for a bit of fun, see

http://mensanator.com/rotanasnem/cherries/cherries.htm"
 
Last edited by a moderator:
Chuckles
 

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