Understanding Attenuation Lengths for Radioactive Materials in Hollow Spheres

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The discussion focuses on calculating attenuation lengths for gamma rays emitted from a small radioactive sphere placed inside a larger hollow sphere made of a different material. When determining the distance a gamma ray travels before absorption, if the calculated length L exceeds the distance within the inner sphere, a new calculation for the outer sphere's material is necessary. If both materials have the same attenuation properties, the lengths can be simply added together. The conversation emphasizes the importance of recalculating L based on the material properties when transitioning between different materials. This approach ensures accurate modeling of gamma ray behavior in heterogeneous environments.
Marioqwe
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Hello, I am reading this article in wikipedia http://en.wikipedia.org/wiki/Attenuation_length about attenuation lengths and there is something I'm hoping someone here can explain to me.

Lets say I have one small solid sphere and one big hollow sphere. And let's say I put the small sphere within the hollow part of the big one.
Now, somehow the small sphere is radioactive and it emits gamma rays. The big sphere is made of a different material (not radioactive). Also, let's say I have solved the equation in the wiki article for the length L = -λln(rand(0,1)). Then, I solve for L using λ for the radioactive material. But what happens if this L happens to be big enough to exit the first material and it goes into the second one. Would I have to calculate L again using λ for the non-radioactive material?
 
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You want to calculate a random length L (for a single particle) for the flight distance to the point of absorption? In this case, if both materials are equal, just add the lengths in the materials. Alternatively, if L is longer than the flight distance in the inner object, do the same calculation again for the outer object, with a new L' for the length in this material only.
 
mfb said:
You want to calculate a random length L (for a single particle) for the flight distance to the point of absorption?

Exactly.

mfb said:
In this case, if both materials are equal, just add the lengths in the materials. Alternatively, if L is longer than the flight distance in the inner object, do the same calculation again for the outer object, with a new L' for the length in this material only.

Thank you.
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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