Understanding Coplanar Parallelepiped in Vector Algebra

  • Thread starter Thread starter cicatriz
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 4K views
cicatriz
Messages
3
Reaction score
0
I have just completed a question in which I have determined:

(axb).c = 0 = det [a,b,c]

Where: a = (1,1,2) b = (2,3,4) c = (1,-2,2)


With some googling, I established this meant the parallelepiped to be coplanar but I'm not sure exactly what this means. If anyone could offer me some assistance with this I would be most grateful.


Cicatriz
 
Physics news on Phys.org
It means that all of the edges of your parallelepiped lie in the same plane. So the box is squashed flat and has no volume.
 
Dick said:
It means that all of the edges of your parallelepiped lie in the same plane. So the box is squashed flat and has no volume.

Thanks!