Determinants and parallelepiped

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kristo
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Homework Statement


For the determinant [tex] \left| \begin{array}{ccc} a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \\ c_1 & c_2 & c_3 \end{array} \right| [/tex] , b and c being the base of a parallelepiped
why is the equation [tex]\vec b \cdot (a_1^{'}e_1 + a_2^{'} e_2 + a_3^{'} e_3) = 0[/tex] (same goes for vector c) true? Where a' is a minor of the determinant and e a unit vector.


The Attempt at a Solution


Well, it makes sense algebraically, but as to the geometrical interpretation, I don't really understand it. The vector a'e is is supposedly perpendicular to vector b and also c, but how come?
 
on Phys.org
consider the determinant method for calculating a cross product...

if you still don't get it try writing out what the minors are...