Understanding displacements of points by interpreting directions

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The discussion focuses on the displacement of points in Euclidean space, specifically how point x is displaced to point x1 using the formula x1 = x + a(x - y). It is established that a positive value of a increases the distance from point x1 to point y, while a negative value decreases this distance. The vector interpretation of the displacement is clarified, where (x - y) represents the direction (force) from point y to point x. The conversation emphasizes the geometric implications of this displacement through vector addition.

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Suppose that points x and y are given in Euclidean space. Point x is displaced to point x1 by

x1=x+a(x-y)

Given that a is positive number, how can it be shown that the distance x1 to y is larger than distance x to y. I'm mainly interested in a vector interpretation of the above update rule. In that sense, can (x-y) in the above rule be interpreted as
direction (force) from point y to point x? Similar interpretation is welcome.

Given negative a, the update is x1=x+a(y-x), so now the above intuition of a force is direction from point x to point y.
 
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hi onako! :smile:
onako said:
… can (x-y) in the above rule be interpreted as
direction (force) from point y to point x?

yes, that's exactly correct :smile:

x-y is the vector ##\vec{YX}##, with magnitude |YX| and direction from Y to X
 
So, adding a(x-y) to x, means that the distance x to y changes depending on a: positive a implies increased distance, and negative a implies decreased distance? It's a bit "non-rigid" to state that a vector is added to a point.
 
onako said:
So, adding a(x-y) to x, means that the distance x to y changes depending on a: positive a implies increased distance, and negative a implies decreased distance? It's a bit "non-rigid" to state that a vector is added to a point.

ah, no, it isn't added to a point, it's added to the vector ##\vec{OX}## …

##\vec{OX} + a\vec{XY} = \vec{OX_1}## :smile:

draw the triangle, and you'll see why! :wink:
 

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