Understanding displacements of points by interpreting directions

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Discussion Overview

The discussion revolves around the interpretation of displacements of points in Euclidean space, specifically focusing on the update rule for point displacement and its implications on distances between points. Participants explore vector interpretations of the displacement and the effects of varying the parameter 'a' on distances.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant proposes that the displacement of point x to point x1 can be interpreted as a vector addition involving the direction from point y to point x, represented by (x-y).
  • Another participant confirms this interpretation, stating that (x-y) is indeed the vector from y to x, with its magnitude and direction clearly defined.
  • A participant questions whether the addition of a(x-y) to x results in a change in distance to point y, suggesting that positive values of a increase the distance while negative values decrease it.
  • A later reply clarifies that the vector is not added directly to a point but rather to the vector representation of point x, indicating a geometric interpretation involving vectors.

Areas of Agreement / Disagreement

Participants generally agree on the vector interpretation of the displacement, but there is some uncertainty regarding the implications of adding a vector to a point and how it affects distances. The discussion remains somewhat unresolved regarding the conceptualization of vector addition in this context.

Contextual Notes

Participants express different views on the rigidity of vector addition to points and its geometric implications, indicating a need for clearer definitions and visual representations to fully understand the concepts discussed.

onako
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Suppose that points x and y are given in Euclidean space. Point x is displaced to point x1 by

x1=x+a(x-y)

Given that a is positive number, how can it be shown that the distance x1 to y is larger than distance x to y. I'm mainly interested in a vector interpretation of the above update rule. In that sense, can (x-y) in the above rule be interpreted as
direction (force) from point y to point x? Similar interpretation is welcome.

Given negative a, the update is x1=x+a(y-x), so now the above intuition of a force is direction from point x to point y.
 
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hi onako! :smile:
onako said:
… can (x-y) in the above rule be interpreted as
direction (force) from point y to point x?

yes, that's exactly correct :smile:

x-y is the vector ##\vec{YX}##, with magnitude |YX| and direction from Y to X
 
So, adding a(x-y) to x, means that the distance x to y changes depending on a: positive a implies increased distance, and negative a implies decreased distance? It's a bit "non-rigid" to state that a vector is added to a point.
 
onako said:
So, adding a(x-y) to x, means that the distance x to y changes depending on a: positive a implies increased distance, and negative a implies decreased distance? It's a bit "non-rigid" to state that a vector is added to a point.

ah, no, it isn't added to a point, it's added to the vector ##\vec{OX}## …

##\vec{OX} + a\vec{XY} = \vec{OX_1}## :smile:

draw the triangle, and you'll see why! :wink:
 

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