Understanding E Multiplication: Solving Odd Equations with Exponents

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The discussion revolves around solving the equation involving exponential functions and understanding the manipulation of exponents. Participants express confusion about the transformation of terms, particularly how e^{2t} multiplied by 2e^{2t} results in 2e^{4t}. Clarifications are provided about the rules of exponents, emphasizing that e^{2t} * e^{2t} equals e^{4t}, not (e^{2t})^{2t}. The importance of correctly applying algebraic rules in exponential functions is highlighted, with examples illustrating the principles. Overall, the conversation centers on grasping the correct application of exponent rules in the context of the given equation.
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<br /> \frac{{{\rm e}^{{\rm 2t}} }}{{\sqrt {e^{4t} + t} }}*2e^{2t} = \frac{{{\rm 2e}^{{\rm 4t}} }}{{\sqrt {e^{4t} + t} }}<br />
Is that true? What am i not realizing here...
 
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Pengwuino said:
<br /> \frac{{{\rm e}^{{\rm 2t}} }}{{\sqrt {e^{4t} + t} }}*2e^{2t} = \frac{{{\rm e}^{{\rm 4t}} }}{{\sqrt {e^{4t} + t} }}<br />
Is that true? What am i not realizing here...

you left out the factor of 2 in the numerator
 
oops yah i did... ill fix that

but is that true? I can't seem to grasp it... and its midnight so i don't think i will be able to easily realize what's going on

I was thinking that it should just be 3e^2t... and I don't understand how it just got turned into e^4t
 
Pengwuino said:
oops yah i did... ill fix that
but is that true? I can't seem to grasp it... and its midnight so i don't think i will be able to easily realize what's going on
I was thinking that it should just be 3e^2t... and I don't understand how it just got turned into e^4t
No, e^{2t} + 2 e^{2t} would be equal to 3 e^{2t}.
e^{2t} * 2 e^{2t} = 2 (e^{2t})^2 = 2 e^{4t}

Or for an even more straight forward example,
x + 2x = 3x
x * 2x = 2x^2
 
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youre lucky though, since the e^x function was proven to be exponential, thus it follows the rules of exponents, just like anything else. the rest is just algebra.
2^2 * 2^2=4 * 4=16=2^4
or more generally
x^a * x^b=x^{ab} for all bases that correspond to exponential functions. since the "e" function is exponential, you can use these laws.
have fun
 
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there is a square missing:
e^{2t} * 2 e^{2t} = 2 (e^{2t})^{2t} = 2 e^{4t^2}
 
gerben said:
there is a square missing:
e^{2t} * 2 e^{2t} = 2 (e^{2t})^{2t} = 2 e^{4t^2}

e^{2t}* e^{2t}=e^{2t+2t}, not (e^{2t})^{2t}
 
Pengwuino said:
oops yah i did... ill fix that

but is that true? I can't seem to grasp it... and its midnight so i don't think i will be able to easily realize what's going on

I was thinking that it should just be 3e^2t... and I don't understand how it just got turned into e^4t

lol i thought that's what the problem was, where did the 2 go? :-p
 

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