Understanding Impulsive & Non-Impulsive Forces in Linear Momentum

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SUMMARY

This discussion focuses on the application of the principle of linear impulse and momentum, specifically distinguishing between impulsive and non-impulsive forces. An impulsive force is defined as one that acts over a very short time, while non-impulsive forces, such as normal force and friction, can also influence momentum conservation. The equation m(v1) + ∑ ∫ (F)dt = m(v2) is central to understanding momentum changes, and momentum is conserved in systems not subject to external forces, even when friction is present, provided all relevant forces are accounted for.

PREREQUISITES
  • Understanding of linear impulse and momentum principles
  • Familiarity with the concepts of impulsive and non-impulsive forces
  • Knowledge of momentum conservation laws
  • Basic proficiency in solving physics problems involving forces and motion
NEXT STEPS
  • Study the application of the impulse-momentum theorem in various scenarios
  • Explore examples of systems with both impulsive and non-impulsive forces
  • Learn how to analyze momentum conservation in systems with friction
  • Investigate the role of external forces in momentum conservation
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Physics students, educators, and professionals in mechanics who seek to deepen their understanding of linear momentum and the effects of different forces on momentum conservation.

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when applying the principle of linear impulse and momentum , how do I know if the force should be considered impulsive or non-impulsive , how should I know if I should consider it in the equation , I already know that an impulsive force is a force that is applied for a very short time ,but in some problems forces such as the normal force were considered impulsive ,for example , there is one containing a crate where the only forces applied are the weight ,normal force ,and friction and still momentum was not conserved , for example , the princip. of impulse and momentum is m(v1) + ∑ ∫ (F)dt =m(v2)
when do I consider the integral to be 0 and momentum conserved
Thank You
 
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Momentum is always conserved for any system not subject to an external force. Even with friction, momentum is conserved but you have to include the momentum change of everything connected with your system, including possibly the Earth itself!

So if you have a frictionless table with inelastic collisions, momentum is still conserved even though kinetic energy is not, because the lack of friction means no communication with anything beyond the cue balls themselves.

The momentum integral ∫Fdt = Δp is similarly applicable. Again, if there is friction, that means whatever the friction is with must be included in the momentum conservation equation.

I would need a more explicit problem description, for example your "crate" problem, to go any further.
 

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