Understanding Lissajous Curves for Fourier Synthesis

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SUMMARY

This discussion focuses on the relationship between Fourier synthesis and Lissajous curves, specifically in the context of plotting spatial data. The user analyzes their x and y data, which represent a wing's circular motion, and applies Fourier synthesis using Fast Fourier Transform (FFT) to derive coefficients for cosine and sine functions. The resulting plot of x against y yields a Lissajous curve instead of the expected ellipse. The user seeks guidance on how to accurately recreate the original elliptical shape using Fourier synthesis.

PREREQUISITES
  • Understanding of Fourier synthesis and its application in signal processing.
  • Familiarity with Fast Fourier Transform (FFT) techniques.
  • Knowledge of Lissajous curves and their mathematical representation.
  • Basic proficiency in plotting functions using software tools like MATLAB or Python.
NEXT STEPS
  • Explore advanced techniques in Fourier synthesis for shape reconstruction.
  • Learn about the mathematical properties of Lissajous curves and their parameters.
  • Investigate the use of phase shifts in cosine and sine functions to achieve desired shapes.
  • Study the application of FFT in different contexts, such as signal analysis and image processing.
USEFUL FOR

This discussion is beneficial for mathematicians, signal processing engineers, and anyone interested in the practical applications of Fourier synthesis and Lissajous curves in data visualization and analysis.

Sam Smith
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i have a question about Fourier synthesis and how this relates to lissajous curves.

I have two sets of test data; spatial data in the x and y directions. When I plot the x data against the y I get an ellipse. ( it represents a wing moving in a circular motion)

I am trying to recreate this shape by means of Fourier synthesis. To do this I look at the fft of my x and y data and get information about the amplitudes of the fundamental frequencies along with harmonics presents in both data sets. The real part I use as the coefficient of my cos and the imaginary as the coefficient of my sin.

And so I say

X(t) = a1* cos(2*pi*f*t) + b1* sin( 2*pi*f*t)

And

Y(t) = aa1* cos(2*pi*f*t) + bb1*sin( 2*pi*f*t) + aa2* cos(4*pi*f*t) + bb2*sin( 4*pi*f*t)

(There was just one peak in the x data and two peaks in the y)

However when I then plot x against y I get a lissajous curve. As I would expect as I am plotting sine waves against sin waves. How can I recreate the original shape? Must I somehow plot cos and sin differently?
 
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