Understanding Matrix Multiplication: Solving Homework Problems (5) and (24)

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The discussion focuses on solving matrix multiplication problems, specifically homework problems (5) and (24). For problem (5), the user successfully calculated MU and MV, finding that MU equals 6U and MV equals 9V. In problem (24), the user derived (A+I)B and confirmed it matched the result for (A+I)21B, realizing that (A+I)B is equivalent to B. The conversation emphasizes understanding the relationships between the matrices involved and how repeated multiplication affects the results. Overall, the thread provides insights into matrix operations and their implications in solving homework problems.
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Homework Statement



DSC00572.jpg
DSC00576.jpg


Homework Equations


The Attempt at a Solution



I need help with (5) and (24). For (5), i can find MU and MV but have difficulty in finding MnU and MnV. For (24), i can solve (i) but don't know how to find (A+I)21B.

The answer for (5): MnU=6nu; MnV=9nV...

As for (24) (A+I)21B =
row1: (-3 1 5)
row2: (6 -2 -10)
row3: (3 -1 -5)

Thanks in advance...
 
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For #5, try calculating MU and MV. Can you express the results in terms of U and V?

For #24, what did you get for (A+I)B? How is it related to B?
 
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vela said:
For #5, try calculating MU and MV. Can you express the results in terms of U and V?

For #24, what did you get for (A+I)B? How is it related to B?

For (5), i get MU=
row1: (6)
row2: (6) and

MV=
(-9)
(18) and i stuck there...For (24), i get (A+I)B=
row1: (-3 1 5)
row2: (6 -2 -10)
row3: (3 -1 -5)
which is same as the answer of (A+I)21B... but i totally don't understand why.. can you help me?

P/S: i managed to find solve (5) already... can you focus on (24)? thanks...
 
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Michael_Light said:
For (5), i get MU=
row1: (6)
row2: (6) and

MV=
(-9)
(18) and i stuck there...
OK, so you have

MU = \begin{pmatrix} 6 \\ 6 \end{pmatrix} = 6\begin{pmatrix} 1 \\ 1 \end{pmatrix} = 6 U

Now if you multiply by M again, you'll get

M^2 U = M(MU) = M(6U) = 6 (MU) = \dots

Can you see how this will work out?
For (24), i get (A+I)B=
row1: (-3 1 5)
row2: (6 -2 -10)
row3: (3 -1 -5)
which is same as the answer of (A+I)21B... but i totally don't understand why.. can you help me?
How is that matrix, (A+I)B, related to B?
 


vela said:
OK, so you have

MU = \begin{pmatrix} 6 \\ 6 \end{pmatrix} = 6\begin{pmatrix} 1 \\ 1 \end{pmatrix} = 6 U

Now if you multiply by M again, you'll get

M^2 U = M(MU) = M(6U) = 6 (MU) = \dots

Can you see how this will work out?

How is that matrix, (A+I)B, related to B?

(A+I)B = B.. okay i understand now... thanks for your help!
 

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